Bootstrapping

Based on Chapter 8 of ModernDive. Code for Quiz 12.

1. Load the R packages we will use:

library(tidyverse)
library(moderndive)
library(infer)
library(fivethirtyeight)

What is the average age of members that have served in congress?

• Set random seed generator to 123
• Take a sample of 100 from the dataset congress_age and assign it to congress_age_100

set.seed(123)

congress_age_100 <- congress_age  %>% 
  rep_sample_n(size=100)

• congress_age is the population and congress_age_100 is the sample

• 18,635 is number of observations in the population and 100 is the number of observations in your sample

Construct the confidence interval

1. Use specify to indicate the variable from congress_age_100 that you are interested in

congress_age_100  %>% 
  specify(response = age)

Response: age (numeric)
# A tibble: 100 × 1
     age
   <dbl>
 1  53.1
 2  54.9
 3  65.3
 4  60.1
 5  43.8
 6  57.9
 7  55.3
 8  46  
 9  42.1
10  37  
# … with 90 more rows

2. Use generate 1000 replicates of your sample of 100

congress_age_100  %>% 
  specify(response = age)  %>% 
  generate(reps = 1000, type= "bootstrap")

Response: age (numeric)
# A tibble: 100,000 × 2
# Groups:   replicate [1,000]
   replicate   age
       <int> <dbl>
 1         1  42.1
 2         1  71.2
 3         1  45.6
 4         1  39.6
 5         1  56.8
 6         1  71.6
 7         1  60.5
 8         1  56.4
 9         1  43.3
10         1  53.1
# … with 99,990 more rows

3. calculate the mean for each replicate

• Assign to bootstrap_distribution_mean_age
• Display bootstrap_distribution_mean_age

bootstrap_distribution_mean_age  <- congress_age_100  %>% 
  specify(response = age)  %>% 
  generate(reps = 1000, type = "bootstrap")  %>% 
  calculate(stat = "mean")
bootstrap_distribution_mean_age

Response: age (numeric)
# A tibble: 1,000 × 2
   replicate  stat
       <int> <dbl>
 1         1  53.6
 2         2  53.2
 3         3  52.8
 4         4  51.5
 5         5  53.0
 6         6  54.2
 7         7  52.0
 8         8  52.8
 9         9  53.8
10        10  52.4
# … with 990 more rows

4. Visualize the bootstrap distribution

visualize(bootstrap_distribution_mean_age)

Calculate the 95% confidence interval using the percentile method

• Assign the output to congress_ci_percentile
• Display congress_ci_percentile

congress_ci_percentile <- bootstrap_distribution_mean_age %>% 
  get_confidence_interval(type = "percentile", level = 0.95)

congress_ci_percentile

# A tibble: 1 × 2
  lower_ci upper_ci
     <dbl>    <dbl>
1     51.5     55.2

Calculate the observed point estimate of the mean and assign it to obs_mean_age

• Display obs_mean_age

obs_mean_age  <-  congress_age_100  %>% 
  specify(response = age)  %>% 
  calculate(stat = "mean")  %>% 
  pull()

obs_mean_age

[1] 53.36

• Shade the confidence interval

• Add a line at the observed mean, obs_mean_age, to your visualization and color it “hotpink”

visualize(bootstrap_distribution_mean_age) +
  shade_confidence_interval(endpoints = congress_ci_percentile) + 
  geom_vline(xintercept = obs_mean_age, color = "hotpink", size = 1 )

• Calculate the population mean to see if it is in the 95% confidence interval

• Assign the output to pop_mean_age

• Display pop_mean_age

pop_mean_age  <- congress_age  %>% 
  summarize(pop_mean= mean(age))  %>% pull()

pop_mean_age

[1] 53.31373

• Add a line to the visualization at the, population mean, pop_mean_age, to the plot color it “purple”

visualize(bootstrap_distribution_mean_age) +
  shade_confidence_interval(endpoints = congress_ci_percentile) + 
   geom_vline(xintercept = obs_mean_age, color = "hotpink", size = 1) +
   geom_vline(xintercept = pop_mean_age, color = "purple", size = 3)

Save previous plot to preview.png and add to the yaml chunk at the top

ggsave(filename = "preview.png", 
       path = here::here("_posts", "2022-04-11-bootstrapping"))

• Is population mean the 95% confidence interval constructed using the bootstrap distribution? yes

Change set.seed(123) to set.seed(4346). Rerun all the code.

• When you change the seed is the population mean in the 95% confidence interval constructed using the bootstrap distribution? no

• If you construct 100 95% confidence intervals approximately how many do you expect will contain the population mean? 95